{"id":73947,"date":"2019-04-18T07:34:49","date_gmt":"2019-04-18T05:34:49","guid":{"rendered":"http:\/\/www.dandavats.com\/?p=73947"},"modified":"2019-04-18T21:39:42","modified_gmt":"2019-04-18T19:39:42","slug":"kids-bhagavatam-1-3-summary-video-from-lightofgodhead","status":"publish","type":"post","link":"https:\/\/www.dandavats.com\/?p=73947","title":{"rendered":"Kids Bhagavatam 1.3 Summary Video from LightofGodhead"},"content":{"rendered":"

\"\"<\/p>\n

SB 1.3 Summary Video<\/h1>\n
\n
\n
\n
\n
\n
\n

Here is the short summary of SB 1.3 \u2013 Krsna is the source of All Incarnations<\/a>:<\/p>\n

    \n
  1. Verses 1-5: Suta Gosv\u0101m\u012b summarizes how the Lord expands as the three puru\u1e63a avataras for the sake of creation. He mentions that the second puru\u1e63a is the source of all the incarnations within the universe, 22 of which he will
    \n mention next.<\/li>\n
  2. Verses 6-29: Suta Gosv\u0101m\u012b answers the fifth question by the sages \u2013 \u201cWhat does the Lord do when he comes here\u201d, by mentioning 22 incarnations and their activities. He concludes this section by saying that Sri Krsna is the ultimate
    \n source of all the incarnations and is Svayam Bhagavan (1.3.28).<\/li>\n
  3. Verses 30-39: Suta Gosv\u0101m\u012b clarifies that the living entity has a transcendental form beyond gross and subtle forms. One can understand this only by pure devotional service, which is when one can also understand that the Lord\u2019s
    \n form, birth and activities are always transcendental though he appears in this world.<\/li>\n
  4. Verses 40-44: Suta Gosv\u0101m\u012b answers sixth question by the sages \u2013 \u201cWhere to find religion after Krsna departed this world\u201d, by mentioning that in this dark age of Kali, one can find light in Srimad Bhagavatam, which is as brilliant
    \n as the Sun. He shall speak this Bhagavatam as he heard from \u015aukadeva Gosv\u0101m\u012b and as he realized it.<\/li>\n<\/ol><\/div>\n<\/p><\/div>\n<\/p><\/div>\n<\/p><\/div>\n<\/p><\/div>\n<\/div>\n